Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Z is Noetherian but not Artinian as a module over itself

Example

The regular Z-module Z is Noetherian but not Artinian. See Noetherian modules: every submodule is finitely generated.

Facts & Assumptions

Given: The hypotheses and objects in the Example.

[L1]

A left R-module M is Noetherian when every submodule of M is finitely generated (def-generated-cyclic-finitely-generated-and-free-modules). This finite-generation definition is the convention; its equivalence with ACC and the maximal condition is proved in thm-equivalent-characterizations-of-noetherian-modules. (Noetherian modules: every submodule is finitely generated).

[L2]

A left R-module M is Artinian when every descending chain M0M1 of submodules stabilizes: there is N such that Mn=MN for all nN. This is the descending chain condition. (Artinian modules by the descending chain condition).

[L3]

Every subgroup H(Z,+) equals nZ=n for exactly one nN; in particular every subgroup is cyclic. (Every subgroup of (Z,+) is n=nZ for exactly one natural number n).

Verification

technique · direct
1.1

Every subgroup of Z is principal, so every submodule is finitely generated.

L1L2L3givenalgebra
2.1

The descending chain 2nZ is strict from n=0 onward, showing failure of DCC.

step 1.1givenalgebra
3.1

The chain of step 2.1 begins at 20Z=Z, the whole module, and each inclusion 2nZ2n+1Z is strict because 2n2n+1Z; so the chain never stabilizes and DCC fails from the first term onward. This proves the stated claim.

step 2.1givenalgebra

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 59 results over 17 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources