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A monad morphism induces restriction of algebras and a natural comparison of free algebras
Statement
A monad morphism on induces a functor over , defined by restriction of algebra structure. Its components also define a natural transformation from the free -algebra functor to the free -algebra functor followed by .
Facts & Assumptions
Given: A monad morphism on .
The equations for are and (Morphisms between monads on one category).
An -algebra satisfies and , and its homomorphisms satisfy (Algebra and algebra homomorphism for a monad).
The free -algebra on is (Free algebra for a monad).
Proof
For an -algebra , put . By [L1]–[L2], , while naturality of and the two multiplication equations give . Thus is a -algebra.
If is an -algebra homomorphism, then by naturality of . Hence the unchanged underlying arrow is a -algebra homomorphism, and unchanged identities and composites define a functor over .
For every , the multiplication equation in [L1] says precisely that is a -algebra homomorphism. Naturality of makes these maps natural in , giving the claimed comparison of free algebras.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 11 results over 9 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- S. Mac Lane, Categories for the Working Mathematician, 2nd ed., Exercise VI.2.3 (standard reference, not scraped)