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TheoremStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
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The Eilenberg–Moore forgetful functor creates every colimit in the base that the monad and its square preserve

Statement

Let D:JCT be a diagram of algebras whose underlying diagram has a colimit (Q,ij) in C. If both T and T2 preserve this colimit, then there is a unique algebra structure on Q making every ij an algebra homomorphism, and the resulting cocone is a colimit in CT. Thus UT creates every such colimit.

Facts & Assumptions

Given: The diagram, its structure maps aj, the base colimit (Q,ij), and preservation of that colimit by T and T2.

Proof

technique · direct
1.1

Since T preserves the colimit, the maps ijaj:TUTDjQ induce a unique a:TQQ satisfying aT(ij)=ijaj for every j.

givenL1
2.1

Precomposition with every ij proves aηQ=1Q. Precomposition with every T2(ij) proves aT(a)=aμQ; these families are jointly epic because T and T2 preserve the colimit, so (Q,a) is an algebra and every ij is an algebra homomorphism.

step 1.1given
3.1

Any algebra cocone has a unique underlying mediating arrow u:QX; precomposition with every T(ij) shows ua=xT(u), so u is automatically an algebra homomorphism. This proves the lifted universal property and the conditional creation claim.

step 1.1step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 17 results over 8 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources