Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
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An algebraic extension containing a root of every nonconstant base polynomial is algebraically closed

Statement

Let L/F be algebraic. If every nonconstant polynomial in F[x] has a root in L, then L is algebraically closed. One root-adjoining extension suffices; no iterated tower of root extensions is required.

Facts & Assumptions

Given: An algebraic extension L/F containing a root of every nonconstant polynomial over F.

[L1]

The one-step root condition over a perfect base makes an algebraic extension algebraically closed (The one-step root condition makes an algebraic extension of a perfect field algebraically closed).

[L2]

In positive characteristic, the elements with a suitable p-power in the base form a perfect intermediate field whose polynomials retain the root condition in L (The elements with a pnth power in the base form a perfect subfield carrying the one-step root condition).

Proof

technique · direct
1.1L1L3

If F has characteristic zero, [L3] makes it perfect and [L1] makes L algebraically closed.

1.2L1L2

If F has characteristic p>0, let F′ be the perfect intermediate field from [L2]. The extension L/F′ is algebraic because L/F is algebraic, and [L2] gives the one-step root condition over F′, so [L1] again makes L algebraically closed.

2.1step 1.1step 1.2∎

The characteristic-zero and positive-characteristic cases exhaust all fields and establish the conclusion without repeating the root-extension construction.

Depends on

Used by

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources