Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
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An algebraic extension containing a root of every nonconstant base polynomial is algebraically closed

Statement

Let L/F be algebraic. If every nonconstant polynomial in F[x] has a root in L, then L is algebraically closed. One root-adjoining extension suffices; no iterated tower of root extensions is required.

Facts & Assumptions

Given: An algebraic extension L/F containing a root of every nonconstant polynomial over F.

[L1]

The one-step root condition over a perfect base makes an algebraic extension algebraically closed (The one-step root condition makes an algebraic extension of a perfect field algebraically closed).

[L2]

In positive characteristic, the elements with a suitable p-power in the base form a perfect intermediate field whose polynomials retain the root condition in L (The elements with a pnth power in the base form a perfect subfield carrying the one-step root condition).

Proof

technique · direct
1.1

If F has characteristic zero, [L3] makes it perfect and [L1] makes L algebraically closed.

L1L3
1.2

If F has characteristic p>0, let F be the perfect intermediate field from [L2]. The extension L/F is algebraic because L/F is algebraic, and [L2] gives the one-step root condition over F, so [L1] again makes L algebraically closed.

L1L2
2.1

The characteristic-zero and positive-characteristic cases exhaust all fields and establish the conclusion without repeating the root-extension construction.

step 1.1step 1.2

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 48 results over 10 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources