Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
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Sigma-algebras are closed under countable intersections, differences, symmetric differences, and set limits

Statement

Let A be a sigma-algebra on X. Then A is closed under countable intersections, differences, and symmetric differences. If every term of a sequence (An)nN lies in A, then both lim infnAn and lim supnAn (Limit superior and limit inferior of a sequence of sets) lie in A.

Facts & Assumptions

Given: A sigma-algebra A on X and a sequence (An)nN in A.

[L1]

A sigma-algebra contains the empty set and is closed under complements and countable unions (Sigma-algebras).

[L2]

Set liminf is a countable union of tail intersections, and set limsup is a countable intersection of tail unions (Limit superior and limit inferior of a sequence of sets).

Proof

technique · direct
1.1

De Morgan's identity gives nAn=Xn(XAn)A by [L1]. Finite and empty intersections are included by repeating terms and by =X=X.

L1algebra
2.1

If A,BA, then AB=A(XB)A by step 1.1, and AB=(AB)(BA)A.

step 1.1L1algebra
3.1

Each tail intersection and tail union of (An) belongs to A by step 1.1 and [L1]. Applying countable union and intersection closure once more to the formulas in [L2] puts both lim infnAn and lim supnAn in A.

step 1.1L1L2

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 3 results over 2 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources