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TheoremStatement: Literature-sourcedProof: Literature-sourcedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-17
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The inclusion of a reflective full subcategory is monadic

Statement

If A is a reflective full subcategory of C, then its inclusion I:AC is monadic.

Facts & Assumptions

Given: A reflection RI as in Reflective full subcategory and reflector.

[L1]

A reflection is an adjunction R:CA:I with I the full inclusion (Reflective full subcategory and reflector).

[L2]

Algebras for an idempotent monad are exactly the objects whose unit is invertible, with the unique inverse-unit structure (Algebras for an idempotent monad form a reflective subcategory).

[L3]

An adjunction induces the monad formed from its right adjoint after its left adjoint (Every adjunction induces a monad on the domain of its left adjoint).

[L4]

Every component of the counit of a reflection is an isomorphism (The counit of a reflection is an isomorphism).

Proof

technique · direct
1.1

By [L1] and [L3], the reflection induces the monad T=IR on C with multiplication IεR. By [L4] this multiplication is a natural isomorphism, so T is idempotent (Idempotent monad).

L1L3L4
2.1

By [L2], the Eilenberg–Moore category of T is the full subcategory of objects C for which the reflection unit CIRC is invertible. The comparison sends AA to (IA,IεA), and its essential image is exactly this fixed-object subcategory.

step 1.1L2
3.1

Fullness of I makes the comparison fully faithful, and every algebra (C,ηC1) has the specified isomorphism ηC:CIRC to the comparison image of RC. Thus the comparison is an equivalence, so I is monadic by Monadic and strictly monadic functors.

step 2.1

Depends on

Used by

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Dependency tree · next 3 levels

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Sources