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CorollaryStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
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Algebras for a preorder monad are exactly its fixed objects up to preorder equivalence; on a poset they are its fixed points

Statement

For a monad T on a preorder P, a T-algebra structure exists on p exactly when p and Tp are mutually comparable. On a poset this says exactly that Tp=p.

Facts & Assumptions

Given: A monad T on a preorder P.

[L1]

A T-algebra on p includes an arrow Tpp (Algebra and algebra homomorphism for a monad).

[L2]

The monad unit supplies pTp, and every required diagram between fixed objects of a preorder commutes automatically (On a preorder the monads are exactly the monotone extensive maps with T(Tp) below Tp; on a poset they are exactly the closure operators).

[L3]

Antisymmetry turns mutual comparability into equality (Partial order and partially ordered set).

Proof

technique · direct
1.1

If p carries a T-algebra, [L1] gives Tpp, while [L2] gives pTp; hence the two objects are mutually comparable.

L1L2
2.1

Conversely, if Tpp, the corresponding unique arrow is an algebra structure: its unit and associativity diagrams commute because parallel arrows in a preorder are equal.

L1L2step 1.1
3.1

When P is a poset, [L3] changes mutual comparability into Tp=p, and equality plainly gives the comparison required in step 2.1.

L3step 2.1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 17 results over 9 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources