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The square roots of 1 modulo 360 by the Chinese remainder theorem

Example

The square roots of 1 modulo 360 are

1,19,71,89,91,109,161,179,181,199,251,269,271,289,341,359.

Facts & Assumptions

Given: The factorisation 360=895 into pairwise coprime prime powers.

[L1]

A unit is a square modulo n if and only if it is a square modulo every prime-power factor of n (A unit is a square modulo n exactly when it is a square at every prime-power factor).

[L2]

The number of square roots of a soluble unit is the product of the local root counts (The number of square roots of a unit modulo n is the product of the local counts).

Verification

technique · direct
1.1

The roots of 1 are 1,3,5,7 modulo 8, are 1,8 modulo 9, and are 1,4 modulo 5. By [L1], every combination of these local roots gives a global root, and [L2] gives 422=16 global roots.

L1L2givenalgebra
2.1

Solving the finite CRT systems and reducing modulo 360 gives exactly the displayed representatives. They are distinct, and reducing each one modulo 8, 9, and 5 places it in the corresponding local root set from step 1.1, so [L1] verifies that each square is 1 modulo 360; the count in [L2] proves completeness.

step 1.1L1L2algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 48 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.