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CounterexampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
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Odd-prime tests alone miss the obstruction to 13 being a square modulo 24

Statement refuted

For an even modulus, testing whether a unit is a square modulo every odd prime divisor does not suffice to prove that it is a square modulo the original modulus.

Facts & Assumptions

Given: The unit 13 modulo 24=83.

[L1]

For k3, an odd integer is a square modulo 2k if and only if it is congruent to 1 modulo 8 (Unit square criterion and root count modulo powers of two).

[L2]

A unit square modulo n is a square modulo every prime-power factor of n (A unit is a square modulo n exactly when it is a square at every prime-power factor).

Counterexample

technique · direct
1.1

The only odd prime divisor of 24 is 3, and 131(mod3), so it passes the odd-prime square test. But 135(mod8), and [L1] shows that it is not a square modulo 8.

L1givenalgebra
2.1

If 13 were a square modulo 24, the forward implication in [L2] would make it a square modulo the prime-power factor 8, contradicting step 1.1. Hence the odd-prime test misses the two-part obstruction.

step 1.1L2

Depends on

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Dependency tree · next 3 levels

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