Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-17
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Odd primes represented by a divisor of x2+3

Example

An odd prime p divides x2+3 for some integer x if and only if p=3 or p1(mod3). Equivalently, for every odd prime p3, the congruence x23(modp) is soluble if and only if p1(mod3).

Facts & Assumptions

Given: An odd prime p.

[L1]

For distinct odd primes p,q, (pq)(qp)=(1)(p1)(q1)/4 (Quadratic reciprocity for distinct odd primes).

[L2]

For every odd prime p, (1p)=(1)(p1)/2 (First supplement: (1/p)=(1)(p1)/2).

[L3]

For an odd prime p, the Legendre symbol is 1 exactly on the nonzero square classes modulo p (The Legendre symbol, including its zero value).

[L4]

For every odd prime p and integers a,b, (abp)=(ap)(bp) (The Legendre symbol is multiplicative for all integer numerators).

Verification

technique · direct
1.1

Suppose p3. Applying [L1] to 3 and p gives (3/p)(p/3)=(1)(p1)/2=(1/p) by [L2]. Since (3/p) is a sign and [L4] gives (3/p)=(1/p)(3/p), multiplication by (3/p) yields (3/p)=(p/3).

L1L2L4givenalgebra
2.1

By [L3], x23(modp) is soluble exactly when (3/p)=1. For p3, step 1.1 makes this equivalent to (p/3)=1, and the nonzero square classes modulo 3 consist only of 1, so this is equivalent to p1(mod3). For p=3, the class x=0 directly satisfies x23(mod3).

step 1.1L3algebra

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 48 results over 19 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources