Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Quadratic reciprocity for distinct odd primes

Statement

For distinct odd primes p,q, (pq)(qp)=(1)(p1)(q1)/4.

Equivalently, the two Legendre symbols agree unless pq3(mod4), in which case they have opposite signs.

Facts & Assumptions

Given: Distinct odd primes p and q.

[L1]

For distinct odd primes p,q, the lower-half count satisfies (qp)=(1)Sp,q (Gauss's lemma as a lower-half lattice-point count).

[L2]

For the two orientations of the rectangle, Sp,q+Sq,p=(p1)(q1)/4 (The two reciprocity lattice counts partition an open rectangle).

Proof

technique · direct
1.1

Applying [L1] in both orientations, multiplying, and then using [L2] gives (pq)(qp)=(1)Sq,p+Sp,q=(1)(p1)(q1)/4.

L1L2algebra
2.1

The exponent is ((p1)/2)((q1)/2), which is odd exactly when both factors are odd, equivalently when pq3(mod4). Since the Legendre symbols are signs for distinct primes, their product is then 1, and in every other case it is 1, proving the equivalent formulation.

step 1.1algebra

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 33 results over 15 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources