Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedprecheck passaudited 2026-08-17
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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False statement: every group of order 42 has a normal Sylow 2-subgroup

Statement

False claim: every group of order 42 has a normal Sylow 2-subgroup. See Sylow III: np≡1(modp) and np∣m when ∣G∣=pam with p∤m.

Facts & Assumptions

Given: The hypotheses and objects in the false claim.

[L1]

Let ∣G∣=pam with p∤m. Then the number of Sylow p-subgroups satisfies np(G)≡1(modp),np(G)∣m.. (Sylow III: np≡1(modp) and np∣m when ∣G∣=pam with p∤m).

[L2]

Let N and H be groups (def-group), and let α:H→Aut⁡(N) be an action by automorphisms (def-action-by-automorphisms). The external semidirect product N⋊αH is the set N×H with multiplication. ( The external semidirect product N⋊αH).

[L3]

For every prime p, the operations of addition and multiplication on Z/p make it a field (def-field). (For every prime p, the two operations on Z/p make it a field).

Refutation

technique · direct
1.1L1L2L3givenalgebra

We construct the affine group F7⋊F7× of order 42.

2.1step 1.1givenalgebra

Its seven involutions x↦−x+b generate seven Sylow 2-subgroups, so none is normal.

3.1step 2.1L1givenalgebra∎

The translations x↦x+b form a subgroup of order 7, and it is normal because (x↦ax+c) conjugates x↦x+b to x↦x+ab, again a translation; so the group does have a normal Sylow 7-subgroup, and it is only the Sylow 2-subgroups that fail to be normal. The count n2=7 of step 2.1 is consistent with [L1], since 7≡1(mod2) and 7∣21. This proves the stated claim.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources