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For every prime , the two operations on make it a field
Statement
For every prime , the operations of addition and multiplication on make it a field (Field).
Facts & Assumptions
Given: A prime integer .
Modular addition makes an abelian group, modular multiplication makes it a commutative monoid, and both distributive laws hold (For every natural , is an abelian group, multiplication is a commutative monoid operation, and both distributive laws hold).
For positive modulus , is invertible exactly when (For , is a unit if and only if ).
Equality is equivalent to , which means (The congruence class and the quotient set , Congruence modulo an integer: when , including the moduli and ).
A field is a commutative ring with in which every nonzero element is multiplicatively invertible (Field).
Proof
By [L1], all additive, multiplicative, identity, inverse, commutativity, associativity and distributive field axioms already hold except possibly and invertibility of nonzero classes.
Since , it does not divide , so [L4] gives .
If , then by [L4]. Hence by [L2], and [L3] makes invertible.
Steps 1.1 through 1.3 verify every clause of [L5], so is a field.
Depends on
- For every natural $n$, $(\mathbb{Z}/n,+)$ is an abelian group, multiplication is a commutative monoid operation, and both distributive laws hold
- For $n\ge1$, $[a]_n$ is a unit if and only if $\gcd(a,n)=1$
- For a prime $p$ and any integer $a$, $\gcd(p,a)$ is $p$ when $p \mid a$ and $1$ otherwise; so $p \nmid a$ makes $p$ and $a$ coprime
- Prime and composite integers: $p$ is prime when $p > 1$ and its only positive divisors are $1$ and $p$
- Field
- The congruence class $[a]_n$ and the quotient set $\mathbb{Z}/n$
- Congruence modulo an integer: $a\equiv b\pmod n$ when $n\mid(a-b)$, including the moduli $0$ and $1$
Used by
- For an odd prime p, ℚ(ζₚ) has exactly one intermediate field of degree two over ℚ Corollary
- For every prime p, the multiplicative group (ℤ/pℤ)^× is cyclic Corollary
- x²≡ a (mod p) has exactly 1+(a/p) solution classes Corollary
- A set family whose incidence vectors are dependent over F₂ and independent over ℝ Counterexample
- In characteristic 2, a symmetric bilinear form need not have an orthogonal basis Counterexample
- In characteristic 2, distinct quadratic forms can have the same polar form Counterexample
- In ℤ/4 the sets A=B={0,2} have | A+B|=2, below the Cauchy–Davenport bound 3 Counterexample
- Over F₂, the equation x+y=0 has exactly two solutions, so the infinite-field hypothesis is necessary Counterexample
- Over Fₚ, xᵖ-x and the zero polynomial induce the same function but are distinct polynomials Counterexample
- Over ℤ/2, an antisymmetric bilinear form need not be alternating Counterexample
- Power sums need not generate the symmetric ring in characteristic two Counterexample
- The commutator pairing of an extraspecial p-group relative to a chosen generator of its centre Definition
- The Heisenberg group of order p³ over ℤ/p Definition
- The square map of an extraspecial 2-group relative to a chosen generator of its centre Definition
- A dual basis and transpose computed for a linear map on F₃² Example
- A localization of the integers at p need not be Henselian Example
- A nonmonic quadratic congruence solved through its discriminant Example
- beginpmatrix0&11&1 endpmatrix over F₂ has characteristic polynomial x²+x+1 and no eigenvalue in its base field Example
- F₄=F₂[t]/(t²+t+1) with complete addition and multiplication tables Example
- F₈=F₂[t]/(t³+t+1) and its power table Example
- F₉=F₃[t]/(t²+1) and a generator of its multiplicative group Example
- For every integer n>1, nℤ is a maximal ideal of ℤ if and only if n is prime Example
- Frobenius on F₄ swaps the two non-prime-field elements Example
- In characteristic 2, x²+1=(x+1)² has zero derivative and a repeated root Example
- Over F₂, x⁴+x²+1=(x²+x+1)² has two distinct roots, each repeated, in its four-element splitting field Example
- Pairwise independent affine hashing over a prime field Example
- Reduction modulo 2 proves x³+17x+391 irreducible over ℚ Example
- Schwartz zippel for a bivariate polynomial Example
- Spec Z has one generic point and closed prime-number points Example
- Sylow p-subgroups of Aut((ℤ/p)²): nₚ=p+1 Example
- Sylow subgroups of Aff(ℤ/5): n₂=5 and n₅=1 Example
- The 3×3 upper-unitriangular group over a prime field has generator rank two Example
- The affine group AGL(1,p) has one kernel-conjugacy class of complements to its translation subgroup Example
- The finite Heisenberg group is the unique Sylow p-subgroup of its coordinate upper-triangular group Example
- The four-element field (ℤ/2)[x]/(x²+x+1) Example
- The Frattini subgroup of (ℤ/p)ⁿ is trivial Example
- The prime ideals of a field and of the integers Example
- The residue class of t generates F₈^× Example
- ℤ₍ₚ₎ consists of rationals with denominator not divisible by p, has maximal ideal pℤ₍ₚ₎, and residue field Fₚ Example
- FALSE for odd p: the scalar-valued commutator pairing needs no choice of a central generator False statement
…and 31 more results.
Dependency tree · two levels
34 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- K. Conrad, Modular Arithmetic (standard reference, not scraped)
- MIT 18.783 Lecture Notes 3 (standard reference, not scraped)