How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Over , and the zero polynomial induce the same function but are distinct polynomials
Statement refuted
Two formal polynomials over a field are equal whenever they induce the same function on that field.
Facts & Assumptions
Given: A prime , the field , and the polynomials and in .
Evaluation substitutes an element into a formal polynomial, while the formal polynomial itself is its coefficient sequence (Evaluation and roots of a polynomial in a commutative target ring).
Fermat's little theorem gives for every integer (Fermat's little theorem: for prime , implies , and always ).
The ring is the quotient (For every , the congruence-class ring is the quotient ring ).
A prime integer is greater than (Prime and composite integers: is prime when and its only positive divisors are and ).
For prime , the quotient ring is a field (For every prime , the two operations on make it a field).
Counterexample
Fact [L5] licenses the field . For every , choose an integer representative; [L2] and [L3] give , so and the zero polynomial induce the same function.
Because [L4] gives , the degrees and are distinct; as a coefficient sequence, has coefficient in degree and is therefore nonzero. Hence [L1] distinguishes from the zero formal polynomial and refutes the statement.
Depends on
- Evaluation and roots of a polynomial in a commutative target ring
- Fermat's little theorem: for prime $p$, $p\nmid a$ implies $a^{p-1}\equiv1\pmod p$, and always $a^p\equiv a\pmod p$
- For every $n\in\mathbb N$, the congruence-class ring $\mathbb Z/n$ is the quotient ring $\mathbb Z/n\mathbb Z$
- Prime and composite integers: $p$ is prime when $p > 1$ and its only positive divisors are $1$ and $p$
- For every prime $p$, the two operations on $\mathbb{Z}/p$ make it a field
Used by
Nothing in the library uses this result yet.
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 94 results over 24 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- Neil Donaldson, Math 120B Notes, Section 22, polynomial functions (standard reference, not scraped)