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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
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For , is a unit if and only if
Statement
Let and . Then is a unit of (The unit group and Euler's totient for ) if and only if
that is, if and only if and are coprime (Coprime integers: ). Consequently the condition depends only on the class .
Facts & Assumptions
Given: A positive integer and an integer .
Integers are coprime exactly when for some integers ( and are coprime if and only if for some integers ; and in that case the only common divisors of and are and , Bézout's identity: for integers not both zero, is the least positive element of ; in particular has an integer solution, Common divisor, and the greatest common divisor , with the convention , Coprime integers: ).
The class is a unit exactly when some satisfies (The unit group and Euler's totient for ).
If an integer divides two integers, it divides every integer linear combination of them (Divisibility is reflexive and transitive on , and is linear: if and then for all integers ; also implies , and ).
Proof
Suppose . By [L1], choose integers with . Reducing this equality modulo gives , so is a unit.
Conversely, suppose is a unit. Choose with . Then , so for some integer , and . By [L1], .
If and , write . A Bézout identity then becomes , so by [L1]; symmetry gives the converse. Thus the criterion is representative independent.
Steps 1.1 and 1.2 prove the equivalence, and step 1.3 proves its final representative-independence assertion.
Depends on
- The unit group $(\mathbb{Z}/n)^\times$ and Euler's totient $\varphi(n)=\lvert(\mathbb{Z}/n)^\times\rvert$ for $n\ge1$
- Bézout's identity: for integers $a, b$ not both zero, $\gcd(a,b)$ is the least positive element of $\{\, ax + by : x, y \in \mathbb{Z} \,\}$; in particular $ax + by = \gcd(a,b)$ has an integer solution
- Common divisor, and the greatest common divisor $\gcd(a,b)$, with the convention $\gcd(0,0) := 0$
- Coprime integers: $\gcd(a,b) = 1$
- $a$ and $b$ are coprime if and only if $ax + by = 1$ for some integers $x, y$; and in that case the only common divisors of $a$ and $b$ are $1$ and $-1$
- Divisibility is reflexive and transitive on $\mathbb{Z}$, and is linear: if $d \mid a$ and $d \mid b$ then $d \mid ax + by$ for all integers $x, y$; also $d \mid a$ implies $d \mid ac$, $-d \mid a$ and $d \mid -a$
Used by
- If gcd(a,n)=1, then a^λ(n)≡1 (mod n) Corollary
- If n has a primitive root, gcd(a,n)=1, m≥1, and xᵐ≡ a (mod n) is solvable, then it has exactly gcd(φ(n),m) solution classes modulo n Corollary
- The discriminant counts roots of Ax²+Bx+C≡0 (mod p) for odd prime p∤ A Corollary
- The generators of a cyclic group of order m are the gᵃ with gcd(a,m)=1, so there are φ(m) of them Corollary
- φ(1)=1, and φ(p)=p-1 for every prime p Corollary
- Two quadratic nonresidues modulo 15 can have a nonresidue product Counterexample
- Quadratic residues and nonresidues modulo an integer Definition
- (ℤ/12)^×={[1],[5],[7],[11]} and φ(12)=4 Example
- (ℤ/8)^×={[1],[3],[5],[7]} is not cyclic because every element squares to [1] Example
- 2 is primitive modulo every power of 5 Example
- A modulus n>1 is composite exactly when two nonzero classes in ℤ/n have product [0]ₙ Example
- Aut(C₈)≅ C₂× C₂ Example
- Hol(C₈) is the group of affine maps x↦ ax+b with a∈{1,3,5,7} Example
- The unique Sylow p-subgroup of Aff(ℤ/p²) Example
- A cyclic group of order n has exactly φ(n) generators Lemma
- For an odd prime p and a primitive root g modulo p, at least one of g and g+p is primitive modulo p² Lemma
- For k≥3, the class of 5 has order 2ᵏ⁻² modulo 2ᵏ Lemma
- For odd prime p, p∤ u, and k≥1, the class of 1+pu has order pᵏ⁻¹ modulo pᵏ Lemma
- A unit square modulo an odd integer has Jacobi symbol one Proposition
- For fixed odd modulus, the Jacobi symbol is a homomorphism on the unit group Proposition
- Quadratic residuosity is representative-independent and the residues are the image of squaring Proposition
- Aut(Cₙ)≅(ℤ/nℤ)^× Theorem
- Euler's criterion: if n has a primitive root, gcd(a,n)=1, and m≥1, then xᵐ≡ a (mod n) is solvable if and only if a^φ(n)/gcd(φ(n),m)≡1 (mod n) Theorem
- Euler's product formula φ(n)=n∏_p∣ n(1-1/p)=∏_pᵏ∥ n(pᵏ-pᵏ⁻¹) for n≥1, stated through a finite injective list of its prime divisors Theorem
- Euler's theorem: if n≥1 and gcd(a,n)=1, then a^φ(n)≡1 (mod n) Theorem
- For a prime p and k≥1, φ(pᵏ)=pᵏ-pᵏ⁻¹ Theorem
- For every positive integer n, ∑_d∣ n, d>0φ(d)=n Theorem
- For every prime p, the two operations on ℤ/p make it a field Theorem
- For gcd(n,q)=1 the image of Gal(F_q(μₙ)/F_q) in (ℤ/n)^× is generated by [q] Theorem
- For k≥3, (ℤ/2ᵏℤ)^×≅ C₂× C_2ᵏ⁻², generated uniquely as (-1)^ε5ʲ Theorem
- Gauss's quadratic-residue lemma Theorem
- K(μₙ)/K is Galois and σ↦ a_σ embeds its Galois group into (ℤ/n)^× Theorem
- Over a commutative ℚ-algebra, CYC(A) has generating function ∑_k≥ 1φ(k)/k log1/1-A(xᵏ) Theorem
- The Legendre symbol is multiplicative for all integer numerators Theorem
Dependency tree · two levels
31 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- K. Conrad, Modular Arithmetic (standard reference, not scraped)
- Mathematics LibreTexts, Euler's phi Function (standard reference, not scraped)
- UW Oshkosh, Number Theory Notes 3 (standard reference, not scraped)