How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
is primitive modulo every power of
Example
For every , the class of is a primitive root modulo .
Facts & Assumptions
Given: The integer and powers of the odd prime .
For an odd prime , an integer with , and , the class of has order modulo (For odd prime , , and , the class of has order modulo ).
If an element has order , then its fourth power has order (In a cyclic group of order , has order ).
An element of order has its th power equal to the identity exactly when (If then iff is an integer multiple of , the powers are distinct, and has exactly elements; if has infinite order then only for ).
A class modulo is a unit exactly when its representative is coprime to , and a primitive root is a unit of order (For , is a unit if and only if , Primitive roots modulo ).
Verification
Modulo , are , so has order . This settles .
Let and let be the order of modulo . Since , [L1] says that has order . Hence [L2] gives .
Reduction modulo and step 1.1 show that by [L3]. Therefore , and step 1.2 yields by [L4]. Since is a unit by [L5], it is primitive by the definition in [L5].
Depends on
- For odd prime $p$, $p\nmid u$, and $k\ge1$, the class of $1+pu$ has order $p^{k-1}$ modulo $p^k$
- In a cyclic group of order $m$, $g^a$ has order $m/\gcd(a,m)$
- If $\operatorname{ord}(g) = n$ then $g^{k} = e$ iff $k$ is an integer multiple of $n$, the powers $g^{0}, \dots, g^{n-1}$ are distinct, and $\langle g \rangle$ has exactly $n$ elements; if $g$ has infinite order then $g^{j} = g^{k}$ only for $j = k$
- For a prime $p$ and $k\ge1$, $\varphi(p^k)=p^k-p^{k-1}$
- For $n\ge1$, $[a]_n$ is a unit if and only if $\gcd(a,n)=1$
- Primitive roots modulo $n$
Used by
Nothing in the library uses this result yet.
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 115 results over 25 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- William Stein, Elementary Number Theory, Theorem 2.5.11 (standard reference, not scraped)