Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

2 is primitive modulo every power of 5

Example

For every k1, the class of 2 is a primitive root modulo 5k.

Facts & Assumptions

Given: The integer 2 and powers of the odd prime 5.

[L1]

For an odd prime p, an integer u with pu, and k1, the class of 1+pu has order pk1 modulo pk (For odd prime p, pu, and k1, the class of 1+pu has order pk1 modulo pk).

[L2]

If an element has order r, then its fourth power has order r/gcd(r,4) (In a cyclic group of order m, ga has order m/gcd(a,m)).

[L5]

A class modulo n is a unit exactly when its representative is coprime to n, and a primitive root is a unit of order φ(n) (For n1, [a]n is a unit if and only if gcd(a,n)=1, Primitive roots modulo n).

Verification

technique · direct
1.1

Modulo 5, 21,22,23,24 are 2,4,3,1, so 2 has order 4. This settles k=1.

L3L4L5algebra
1.2

Let k2 and let r be the order of 2 modulo 5k. Since 24=1+53, [L1] says that 24 has order 5k1. Hence [L2] gives r/gcd(r,4)=5k1.

L1L2
2.1

Reduction modulo 5 and step 1.1 show that 4r by [L3]. Therefore gcd(r,4)=4, and step 1.2 yields r=45k1=φ(5k) by [L4]. Since 2 is a unit by [L5], it is primitive by the definition in [L5].

step 1.1step 1.2L3L4L5

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 115 results over 25 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources