Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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If gcd(a,n)=1, then aλ(n)1(modn)

Statement

If n1 and gcd(a,n)=1, then

aλ(n)1(modn).

Facts & Assumptions

Given: Integers n1 and a with gcd(a,n)=1.

[L1]

λ(n) is the exponent of (Z/n)× (Carmichael's function λ(n) as the exponent of (Z/nZ)×).

[L2]

The class of a is a unit exactly when gcd(a,n)=1 (For n1, [a]n is a unit if and only if gcd(a,n)=1).

[L3]

Every element of a finite group raised to its exponent is the identity (The exponent of a finite group).

Proof

technique · direct
1.1

By [L2], the class of a lies in the unit group modulo n.

L2
2.1

By [L1] and [L3], its λ(n)th power is the identity class, which is the asserted congruence. For n=1, both sides are the unique class and λ(1)=1.

step 1.1L1L3

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 50 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources