Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passaudited 2026-08-13
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(0111) over F2 has characteristic polynomial x2+x+1 and no eigenvalue in its base field

Example

Over F2, the matrix

A=(0111)

has characteristic polynomial x2+x+1 and no eigenvalue in F2.

Facts & Assumptions

Given: The displayed matrix over F2=Z/2Z.

[L1]

Since 2 is prime, Z/2Z is a field, whose only elements are 0 and 1 (For every prime p, the two operations on Z/p make it a field).

[L2]

The spectrum over the base field is exactly the root set in that field of the characteristic polynomial (For every finite-dimensional space, σF(T) is exactly the set of roots in F of χT).

Verification

technique · exhaustive finite computation
1.1

In F2[x], χA(x)=det⁡(x−1−1x−1)=x(x−1)−1=x2+x+1.

L1algebra
2.1

By [L1], the only candidate roots are 0 and 1, and χA(0)=1 while χA(1)=1+1+1=1 in F2.

step 1.1L1algebra
3.1

Thus χA has no root in its base field, and [L2] gives σF2(A)=∅.

step 2.1L2∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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