Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Correspondence theorem for submodules of a quotient module

Statement

For N≤M, inverse image and quotient induce mutually inverse inclusion-preserving bijections between submodules of M/N and submodules of M containing N. They preserve sums, intersections, and successive quotients. See Quotient module M/N with scalar multiplication on additive cosets.

Facts & Assumptions

Given: The hypotheses and objects in the Statement.

[L1]

For N≤M, the additive cosets m+N form the quotient module M/N under the well-defined scalar action r(m+N):=rm+N. (Quotient module M/N with scalar multiplication on additive cosets).

[L2]

Let f:M→P be a module homomorphism and let N≤M satisfy N⊆ker⁡f. There is a unique module homomorphism fˉ:M/N⟶P such that fˉ(m+N)=f(m), equivalently f=fˉ∘π. (A module homomorphism vanishing on N factors uniquely through M/N).

[L3]

If N≤L≤M, then L/N is a submodule of M/N and (M/N)/(L/N)≅M/L. (Third isomorphism theorem for modules).

Proof

technique · direct
1.1L1L2L3givenalgebra

Inverse image and quotient give mutually inverse inclusion-preserving bijections between submodules of M/N and submodules of M containing N.

2.1L3step 1.1givenalgebra∎

If P≤M/N, then π(π−1P)=P by surjectivity of π; if L≤M contains N, then π−1(L/N)=L. Direct calculation with inverse images gives preservation of sums and intersections, while [L3] identifies successive quotients. This proves the stated claim.

Depends on

Used by

Dependency tree · two levels

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Sources