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A module homomorphism vanishing on factors uniquely through
Statement
Let be a module homomorphism and let satisfy . There is a unique module homomorphism
such that , equivalently .
Facts & Assumptions
Given: A module homomorphism and a submodule with .
The canonical map is a surjective module homomorphism with kernel (The canonical map is a surjective module homomorphism with kernel ; thus every submodule is a kernel).
A group homomorphism that kills a normal subgroup factors uniquely through the group quotient (A homomorphism that kills a normal subgroup factors uniquely through the quotient group).
A module homomorphism is additive and scalar-preserving, and its kernel is the preimage of zero (Module homomorphism and isomorphism, kernel, image and cokernel).
Proof
By [L1], the canonical map is an additive-group quotient map with kernel . Viewing the modules as additive groups, [L3] makes a group homomorphism and the hypothesis says it kills . By [L2], define the unique additive homomorphism by , with .
For every coset, , so is scalar-preserving.
Thus is a module homomorphism with the required factorisation.
Any module-homomorphism factor is in particular an additive-group factor, so the uniqueness in step 1.1 proves its uniqueness as a module homomorphism.
Depends on
Used by
- M⊗_RR/I≅ M/IM naturally Corollary
- Symmetric and exterior powers are representations Proposition
- Tangent space of a free proper quotient Proposition
- Tangent space of a homogeneous quotient Proposition
- A module-valued coend is the direct sum of the diagonal values modulo the dinaturality submodule Theorem
- Correspondence theorem for submodules of a quotient module Theorem
- Covariant and contravariant Hom are left exact Theorem
- First isomorphism theorem for modules: M/ker f congimf Theorem
- For every ring R, the category R-Mod is complete and cocomplete Theorem
- Tensoring is right exact Theorem
- The Snake Lemma for modules Theorem
- Third isomorphism theorem for modules Theorem
Dependency tree · two levels
14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- McGerty, Algebra II: Rings and Modules, Section 3 (standard reference, not scraped)