Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-17
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Nonempty intersections of sigma-algebras are sigma-algebras, so the generated sigma-algebra exists and is minimal

Statement

Let X be a set.

  1. The intersection of every nonempty family of sigma-algebras on X is a sigma-algebra on X.
  2. For every EP(X), the family ΣX(E) of The sigma-algebra generated by a family of sets is nonempty, and σX(E) is the unique smallest sigma-algebra on X containing E.

Facts & Assumptions

Given: A set X, a nonempty family S of sigma-algebras on X, and a family EP(X), with ΣX(E) and σX(E) as in The sigma-algebra generated by a family of sets.

Proof

technique · direct
1.1

Every member of S contains ; if A belongs to every member, then so does XA; and if every An belongs to every member, then so does nAn. Hence S is a sigma-algebra on X.

given
1.2

The power set P(X) is a sigma-algebra on X containing E, so P(X)ΣX(E) and the defining intersection for σX(E) is taken over a nonempty family.

givenconstruct
2.1

By step 1.1, σX(E) is a sigma-algebra. Every set in E belongs to every member of ΣX(E), so EσX(E); and the defining intersection is contained in every sigma-algebra containing E. Thus it is the unique smallest such sigma-algebra.

step 1.1step 1.2

Depends on

Used by

Cited to discharge well-definedness by The sigma-algebra generated by a family of sets.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 3 results over 3 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources