How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
is an infinite perfect field of characteristic
Example
Inside an algebraic closure of , let be the unique root of and put . Then
is an infinite perfect field of characteristic containing .
Facts & Assumptions
Given: A prime and an algebraic closure of .
In characteristic , a field is perfect exactly when Frobenius is surjective (A field is perfect exactly when it has characteristic zero or its Frobenius map is surjective).
Frobenius is injective and respects field operations in characteristic (Frobenius is an injective endomorphism in characteristic , and an automorphism for finite fields).
The rational function field is the fraction field of its polynomial ring (For a field , is its rational function field; in particular ).
Verification
The given algebraic closure contains a root of every , and [L2] makes that root unique. Take . Uniqueness gives , so .
A nested union of fields is a field, so is a field of characteristic containing . The distinct powers of the indeterminate show that this fraction field, and hence , is infinite.
If , replace by in the same rational expression. Since coefficients in are fixed by Frobenius, [L2] shows that the resulting element of has th power . Thus Frobenius on is surjective.
By [L1], is perfect.
Depends on
- A field is perfect exactly when it has characteristic zero or its Frobenius map is surjective
- Frobenius $x\mapsto x^p$ is an injective endomorphism in characteristic $p$, and an automorphism for finite fields
- For a field $F$, $F(t)=\operatorname{Frac}(F[t])$ is its rational function field; in particular $\mathbb R(t)=\operatorname{Frac}(\mathbb R[t])$
Used by
Nothing in the library uses this result yet.
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 60 results over 15 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- P. L. Clark, Field Theory, Chapter 4 (standard reference, not scraped)
- J. S. Milne, Fields and Galois Theory, Chapters 3 and 5 (standard reference, not scraped)