Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

For a field F, F(t)=Frac⁡(F[t]) is its rational function field; in particular R(t)=Frac⁡(R[t])

Statement

For every field F, the polynomial ring F[t] is an integral domain, and F(t):=Frac⁡(F[t])={f(t)g(t):f,g∈F[t], g≠0} is a field containing an embedded copy of F[t]. It is called the rational function field over F. In particular, R(t)=Frac⁡(R[t]).

Facts & Assumptions

Given: A field F.

[F2]

If R is an integral domain, then R[t] is an integral domain (A polynomial ring over an integral domain is an integral domain).

[F3]

The field of fractions of a domain consists of fractions with nonzero denominator and is a field containing the domain injectively (The field of fractions Frac⁡(D)=(D∖{0})−1D of an integral domain, Frac⁡(D) is a field and d↦d/1 embeds the integral domain D).

Proof

technique · direct
1.1

By [F1] and [F2], F[t] is an integral domain. Applying [F3] gives the displayed set of fractions, its field structure, and the embedding of F[t].

F1F2F3
2.1

Taking F=R gives the final assertion.

step 1.1∎

Depends on

Used by

Dependency tree · two levels

19 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources