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The filled difference quotient is continuous at its exceptional point and holomorphic away from it
Statement
Let be open, let be holomorphic, and fix . Define
Then is continuous on and holomorphic on . No holomorphy at the filled point is asserted.
Facts & Assumptions
Given: An open set , a holomorphic , and a fixed point .
The derivative is the limit of as through (Complex differentiability at a point, the complex derivative, holomorphic functions, and entire functions).
Sums, differences, and quotients with nonzero denominator of holomorphic functions are holomorphic (Linearity, product, reciprocal, and quotient rules for complex derivatives).
A holomorphic function is continuous (Complex differentiability at a point implies continuity there).
Proof
By [L1], the off-point quotient tends to as , which is exactly continuity of at ; this also covers constant .
On , the numerator and denominator are holomorphic and the denominator is nonzero, so [L2] makes holomorphic there.
By [L3], step 1.2 also makes continuous away from ; together with step 1.1 this proves continuity on all of , without claiming differentiability at the filled point.
Depends on
Used by
Dependency tree · two levels
9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Lars Ahlfors, Complex Analysis, third edition, Ch. 4, Section 2.2 (standard reference, not scraped)