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Based circle loops of equal degree are path-homotopic

Statement

Based circle loops of equal degree are path-homotopic.

Facts & Assumptions

Given: Based loops α,β:IR/Z at [0] with deg(α)=deg(β).

[L1]

Each based circle loop γ has a unique lift γ~ beginning at zero, with deg(γ)=γ~(1) (The degree of a based circle loop).

[L2]

If n1, CRn is convex, and f,g:XC are continuous, then H(x,t)=(1t)f(x)+tg(x) is a continuous homotopy from f to g (For continuous maps into a convex subset of Rn, the straight-line formula defines a continuous homotopy).

[L3]

If v:YZ is continuous and fAg, then vfAvg (Precomposition and postcomposition by continuous maps preserve homotopies, including their relative form).

[L4]

The quotient projection p:RR/Z is continuous (The circle as S1=R/Z with basepoint [0]).

Proof

technique · direct
1.1

Let α~ and β~ be the lifts from [L1]. Both begin at zero, and the degree hypothesis with [L1] gives α~(1)=β~(1).

givenL1
2.1

Since R is convex, [L2] makes H(t,s)=(1s)α~(t)+sβ~(t) continuous. Step 1.1 gives H(0,s)=0 and H(1,s)=α~(1)=β~(1) for every s, so this homotopy fixes both endpoints.

step 1.1L2algebra
3.1

Postcomposing with the continuous quotient projection, [L3] and [L4] give an endpoint-fixed homotopy pH. The defining lift equations in [L1] identify its endpoints as pα~=α and pβ~=β. Hence the loops are path-homotopic.

step 2.1L1L3L4

Depends on

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Dependency tree · next 3 levels

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