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LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
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Based circle loops of equal degree are path-homotopic

Statement

Based circle loops of equal degree are path-homotopic.

Facts & Assumptions

Given: Based loops α,β:I→R/Z at [0] with deg⁡(α)=deg⁡(β).

[L1]

Each based circle loop γ has a unique lift γ~ beginning at zero, with deg⁡(γ)=γ~(1) (The degree of a based circle loop).

[L2]

If n≥1, C⊆Rn is convex, and f,g:X→C are continuous, then H(x,t)=(1−t)f(x)+tg(x) is a continuous homotopy from f to g (For continuous maps into a convex subset of Rn, the straight-line formula defines a continuous homotopy).

[L3]

If v:Y→Z is continuous and f≃Ag, then v∘f≃Av∘g (Precomposition and postcomposition by continuous maps preserve homotopies, including their relative form).

[L4]

The quotient projection p:R→R/Z is continuous (The circle as S1=R/Z with basepoint [0]).

Proof

technique · direct
1.1givenL1

Let α~ and β~ be the lifts from [L1]. Both begin at zero, and the degree hypothesis with [L1] gives α~(1)=β~(1).

2.1step 1.1L2algebra

Since R is convex, [L2] makes H(t,s)=(1−s)α~(t)+sβ~(t) continuous. Step 1.1 gives H(0,s)=0 and H(1,s)=α~(1)=β~(1) for every s, so this homotopy fixes both endpoints.

3.1step 2.1L1L3L4∎

Postcomposing with the continuous quotient projection, [L3] and [L4] give an endpoint-fixed homotopy p∘H. The defining lift equations in [L1] identify its endpoints as p∘α~=α and p∘β~=β. Hence the loops are path-homotopic.

Depends on

Used by

Dependency tree · two levels

17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources