Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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The Borel sigma-algebra of a subspace is the trace of the ambient Borel sigma-algebra

Statement

Let Y be a subspace of a topological space X. Then

B(Y)=B(X)∣Y.

Facts & Assumptions

Given: A topological space X and a subset Y⊆X with its subspace topology.

[L2]

Generating a sigma-algebra commutes with taking traces (Generating a sigma-algebra commutes with taking traces).

[L3]

The Borel sigma-algebra of a topological space is generated by its open sets (The Borel sigma-algebra of a topological space).

Proof

technique · direct
1.1L1L3

By [L1], the family generating B(Y) is precisely the trace on Y of the family generating B(X).

2.1step 1.1L2L3∎

Applying [L2] to the family of open subsets of X gives B(Y)=B(X)∣Y.

Depends on

Used by

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources