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How statement and proof provenance work

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The Arithmetical Hierarchy and Post's Theorem: Examples and Counterexamples

1 · Prerequisites

2 · Summary

These examples make the computation witness in a Σ10 formula and the eventual, rather than effectively timed, nature of a limit approximation concrete.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06Open item page →

Reading a c.e. definition as a Sigma_1^0 formula

Example

The halting set is expressed by ⟨e,x⟩∈K  ⟺  ∃s T(e,x,s), where s encodes a complete halting computation history.

Facts & Assumptions

Given: the fixed computation-history coding for K.

Verification

technique · direct
1.1givenconstruct

Validity of a proposed finite history is primitive recursive, so the displayed formula has one leading unbounded existential quantifier over a bounded matrix.

2.1step 1.1∎

Hence it is a Σ10 presentation. The witness is precisely the finite accepting computation used by the recognizer of K.

ExampleConstruction: Literature-sourcedVerification: AI-generatedverified 2026-09-26 (gpt-6-sol)↗ rests on later materialOpen item page →

A limit approximation computed from the halting oracle

Example

Use the fixed effective numbering ΦeA from the definition of the Turing jump. For 0′={e:Φe∅(e)↓}, put h(e,s)=1 if Φe∅(e) halts within s steps and put h(e,s)=0 otherwise.

Facts & Assumptions

Given: a program index e.

[F1]

The fixed effective numbering defines 0′ by diagonal halting (The Turing jump ↗).

Verification

technique · direct
1.1F1givenconstruct

The numbering and decoder are effective, so bounded simulation makes (e,s)↦h(e,s) computable.

2.1F1step 1.1∎

If Φe∅(e) never halts every value is 0; if it halts at stage r, every value from r onward is 1. Thus lim⁡sh(e,s)=χ0′(e), without supplying a computable stage at which this happens.

CounterexampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06Open item page →

A set lying in both Sigma_n^0 and Pi_n^0

Statement refuted

The assertion that Σn0∩Πn0 is empty for positive n.

Facts & Assumptions

Given: a positive finite level n.

Counterexample

technique · direct
1.1givenconstruct

The set E of even natural numbers has the decidable predicate x=2q for some q, and its complement has the decidable predicate x=2q+1 for some q.

2.1step 1.1∎

Therefore E is Δ10 and is in both Σn0 and Πn0 after padding for every n≥1. It witnesses overlap, not equality of the two classes.

Sources