Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01
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No proper-power relators alone do not prevent torsion outside small cancellation

Statement refuted

No proper-power relators alone prevent torsion, even without any small- cancellation hypothesis.

Facts & Assumptions

Given: The presentation G=a,bab2,a2b.

[L1]

The torsion-free consequence on this page needs the small-cancellation hypothesis as well as the no-proper-power hypothesis (A C prime(1/6) presentation with no proper-power relators defines a torsion-free group).

Counterexample

technique · direct
1.1

As in FALSE: a presentation with no proper-power relators is automatically torsion-free, neither relator ab2 nor a2b is a proper power.

given
2.1

The same substitution calculation gives a=b2 and then b4b=1, so b3=1. Moreover the assignment at, bt to the cyclic group C3=tt3=1 satisfies both relators, so it induces a surjective homomorphism GC3. Thus G has nontrivial torsion.

step 1.1algebra
3.1

Therefore no-proper-power relators do not by themselves prevent torsion. By [L1], the missing small-cancellation hypothesis is essential.

L1step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources