Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A single map exhibiting a quasi-isometry that is discontinuous, non-injective and non-surjective

Statement refuted

A quasi-isometry must be continuous, injective, or surjective.

Facts & Assumptions

Given: The proposed claim together with the witness named in the Statement refuted.

[F1]

A map is (L,C)-coarse Lipschitz when d(f(x),f(x))Ld(x,x)+C, and an (L,C)-quasi-isometric embedding when in addition L1d(x,x)Cd(f(x),f(x)) (Coarse Lipschitz maps and quasi-isometric embeddings).

[L1]

A subset is coarsely dense when every point of the space is within a fixed distance of it, and a quasi-isometry is a coarse Lipschitz map admitting a coarse Lipschitz quasi-inverse (Coarsely dense subsets, quasi-inverses and quasi-isometries).

[L2]

It is written x and called the integer part, or floor, of x. (Integer part: for every real x there is exactly one integer m with mx<m+1).

Counterexample

technique · constructive
1.1

Let f:RR be f(x)=2x/2, whose image is the even integers, and let ι be the inclusion of that image into R. Then ι is coarse Lipschitz, f(2m)=2m for every even integer 2m, and every real x satisfies xf(x)<2; so f is a quasi-isometry.

F1L1L2L3construct
2.1

It is discontinuous at every even integer, non-injective on each half-open interval [2m,2m+2), and misses every odd integer, so all three failures occur in one map.

L2L4step 1.1discharge-construct

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

39 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources