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CounterexampleConstruction: AI-adaptedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
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A subobject lattice of an abelian category need not be distributive

Statement refuted

Every subobject lattice of an object in an abelian category is distributive.

Facts & Assumptions

Given: The abelian group A=(Z/2)⊕(Z/2).

[L1]

Subobject lattices in an abelian category are modular (The subobject lattice of an abelian category is modular).

[L2]

A lattice is distributive when meet distributes over join (Lattices, distributive lattices, and order ideals).

Counterexample

1.1givenalgebra

The nonzero proper subgroups of A are exactly the three one-dimensional subspaces L1=⟨(1,0)⟩,L2=⟨(0,1)⟩,L3=⟨(1,1)⟩. For i≠j, the intersection Li∩Lj is 0, and Li+Lj=A. So the subobject lattice of A is the diamond M3.

2.1L1L2step 1.1∎

Now L1∧(L2∨L3)=L1∧A=L1, while (L1∧L2)∨(L1∧L3)=0∨0=0. Hence the distributive law of [L2] fails in this subobject lattice. By [L1], the example is modular but not distributive.

Depends on

Used by

Dependency tree · two levels

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Sources