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CounterexampleConstruction: AI-generatedVerification: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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A wrong counit can be natural while both triangle identities fail

Statement refuted

For identity functors, any natural choices of unit and counit give the identity adjunction.

Facts & Assumptions

Given: The two-element group C2={1,z} with z2=1.

[F1]

Every monoid is a one-object category, and it is a group exactly when every morphism is invertible (A monoid is a one-object category, and a group is a one-object category in which every morphism is invertible).

[F2]

An adjunction requires (εF)(Fη)=1F and (Gε)(ηG)=1G (Adjunction by unit, counit, and the triangle identities).

Counterexample

technique · direct
1.1F1construct

Regard C2 as a one-object category C by [F1] and set F=G=1C. Choose the identity element as the component of η and z as the component of ε.

2.1step 1.1F2algebra

Both transformations are natural because C2 is abelian, but each triangle composite is z1=z≠1. Hence both identities in [F2] fail.

3.1step 2.1F2∎

Replacing ε by the identity element makes both composites equal to 1, recovering the identity adjunction and isolating the failure in the wrong counit.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources