Alphabeta Math
CounterexampleConstruction: AI-generatedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A wrong counit can be natural while both triangle identities fail

Statement refuted

For identity functors, any natural choices of unit and counit give the identity adjunction.

Facts & Assumptions

Given: The two-element group C2={1,z} with z2=1.

[F1]

Every monoid is a one-object category, and it is a group exactly when every morphism is invertible (A monoid is a one-object category, and a group is a one-object category in which every morphism is invertible).

[F2]

An adjunction requires (εF)(Fη)=1F and (Gε)(ηG)=1G (Adjunction by unit, counit, and the triangle identities).

Counterexample

technique · direct
1.1

Regard C2 as a one-object category C by [F1] and set F=G=1C. Choose the identity element as the component of η and z as the component of ε.

F1construct
2.1

Both transformations are natural because C2 is abelian, but each triangle composite is z1=z1. Hence both identities in [F2] fail.

step 1.1F2algebra
3.1

Replacing ε by the identity element makes both composites equal to 1, recovering the identity adjunction and isolating the failure in the wrong counit.

step 2.1F2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 17 results over 9 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources