Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-13
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An annihilating polynomial need not be minimal: 2 is a root of both x22 and x44

Statement refuted

Every nonzero polynomial that vanishes at an algebraic element is that element's minimal polynomial.

Counterexample

Let a=2, whose nonnegative real value satisfies a2=2 because R is complete (The Cauchy-sequence reals have the least-upper-bound property, Square roots exist: a unique a0 with (a)2=a; the positives are {x2:x0}). Then both x22 and x44 vanish at a, but only the first is minimal.

Facts & Assumptions

Given: The algebraic number a=2 over Q.

[F1]

Eisenstein's criterion proves irreducibility over Q under its prime divisibility hypotheses (Eisenstein criterion over the integers).

[F2]

The minimal polynomial is the unique monic irreducible generator of the evaluation kernel, and it divides every annihilating polynomial (The evaluation kernel and the unique monic irreducible minimal polynomial of an algebraic element).

Verification

technique · counterexample
1.1

Evaluation gives a22=0 and a44=0.

F3algebra
2.1

The polynomial x22 satisfies [F1] at 2, so [F2] identifies it as the minimal polynomial of a over Q.

F1F2step 1.1
3.1

The other annihilator factors as x44=(x22)(x2+2) and has larger degree, so it is a proper multiple of the minimal polynomial.

step 2.1algebra
4.1

Thus a polynomial may annihilate an algebraic element without being its minimal polynomial.

step 1.1step 3.1

Depends on

Used by

Nothing in the library uses this result yet.

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Direct dependencies and their dependencies through the next three levels: 78 results over 16 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources