Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passaudited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Re(1/z) is harmonic on a punctured disc and does not extend harmonically across 0

Statement refuted

Refuted claim: every harmonic function on a punctured disc extends harmonically across the puncture.

The witness is

u(z)=Re⁡(1/z).

It is harmonic on 0<∣z∣<1, but it is unbounded near 0 and therefore does not extend harmonically there.

Facts & Assumptions

Given: The function f(z)=1/z on 0<∣z∣<1 and its real part u(z)=Re⁡(f(z)).

[L3]

A bounded harmonic function near an isolated puncture does extend harmonically (A bounded harmonic function near an isolated puncture extends harmonically).

Counterexample

technique · direct
1.1L1L2

By [L1], the function 1/z is holomorphic on 0<∣z∣<1, so [L2] makes u(z)=Re⁡(1/z) harmonic there.

1.2L3algebra

On the positive real axis, u(t)=1/t→+∞ as t↓0, so u is unbounded near 0. If u had a harmonic extension across 0, it would be bounded on some small closed disc around 0, contradicting [L3].

2.1step 1.1step 1.2∎

Therefore u is harmonic on the punctured disc but does not extend harmonically across the puncture.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

24 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources