Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-29
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A completed-product measurable set can have a nonmeasurable exceptional section

Statement refuted

Every section of a completed-product measurable function is measurable.

Counterexample

technique · direct

Let NR be non-Lebesgue-measurable and let E:={0}×NR2. Put f:=1E.

Facts & Assumptions

Given: The function f=1E above.

[L1]

The set E={0}×N is contained in a planar null set, so it becomes measurable after completing the product measure. (A nonmeasurable subset of a null line shows that the product of complete measures need not be complete)

Verification

1.1

By [L1], the indicator f is measurable for the completed product measure.

L1
2.1

The section at 0 is f0=1N, whose support N is not Lebesgue measurable. Hence f0 is not measurable. So completed-product measurability gives section measurability only almost everywhere, not at every parameter.

step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources