Alphabeta Math
CounterexampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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In a,bab\langle a,b\mid ab\rangle, the trivial word baba is stuck under free cancellation and delete-only relator rewriting

Statement refuted

Consider the following specific syntactic procedure for a displayed finite presentation: at each step, freely cancel an adjacent inverse pair or delete a contiguous occurrence of one displayed relator or its inverse. Never insert a relator and never lengthen the word.

The false claim is that this delete-only procedure reduces every word that represents the identity to the empty word. In a,bab\langle a,b\mid ab\rangle, the word baba represents the identity but admits no step at all.

Facts & Assumptions

Given: The presentation G=a,babG=\langle a,b\mid ab\rangle and the delete-only procedure just stated.

[F1]

In a presented group, every displayed relator becomes the identity (Group presentation by generators and relations).

[F2]

In a group, an equation yx=eyx=e determines y=x1y=x^{-1} (Group and abelian group).

Counterexample

technique · direct
1.1

The relation ab=eab=e gives b=a1b=a^{-1} by [F2], and therefore ba=a1a=eba=a^{-1}a=e in GG.

F1F2
1.2

The word baba has no adjacent inverse pair and contains neither the relator abab nor its inverse b1a1b^{-1}a^{-1} as a contiguous subword.

given
2.1

Thus baba represents the identity by step 1.1 but is stuck and nonempty under the stated procedure by step 1.2, refuting the claim.

step 1.1step 1.2

Depends on

Used by

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Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 19 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.