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Density continuity can violate conservative advection balance
Statement refuted
A universal junction rule declaring the density equal on every incident edge always conserves mass for advection with unequal edge speeds.
Counterexample model
Use one incoming edge with speed and two outgoing edges with speeds and . Mass flux on an edge is stipulated to be speed times density. Giving all incident edges density yields incoming flux and total outgoing flux , so mass is not conserved. A conservative routing can instead send the full incoming flux to the speed- outgoing edge and zero to the other.
The arrows indicate the stipulated flow direction and speeds; the exact flux sums in the refutation, not the drawing, establish the failure.
\begin{center} \begin{tikzpicture}[>=stealth, every node/.style={font=\small}] \node[circle,draw] (v) at (0,0) {junction}; \node[left] (in) at (-2.1,0) {in: }; \node[right] (out1) at (2.2,1.0) {out: }; \node[right] (out2) at (2.2,-1.0) {out: }; \draw[->] (in) -- (v); \draw[->] (v) -- (out1); \draw[->,dashed] (v) -- (out2); \end{tikzpicture} \end{center}
Facts & Assumptions
Given: The stipulated one-in/two-out junction, positive speeds , , , and mass flux .
A conservative routing matrix is nonnegative with unit sums down each incoming column (Conservative nonnegative network advection routing).
Such a routing maps any nonnegative incoming flux to a nonnegative outgoing flux with the same total (A conservative routing matrix preserves total flux).
Refutation
Given: The junction velocities and density-to-flux relation in the Counterexample.
If density is continuous with value on all three incident edges, the incoming flux is , while the outgoing total is . These are unequal, so this junction rule fails mass conservation in the stipulated model.
The matrix is entrywise nonnegative and its sole incoming column sums to . With incoming flux , it produces , whose total is by [F1, F2]. The corresponding outgoing densities are , so this conservative routing does not impose equal densities.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Mario Arioli and Michele Benzi, A Finite Element Method for Quantum Graphs, Emory CS Technical Report TR-2015-009 (44-page full text) (standard reference, not scraped)
- Ward Whitt, Continuous-Time Markov Chains, full lecture notes (2006) (standard reference, not scraped)