Alphabeta Math
CounterexampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-28
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The function e^(1/z) shows that essential singularities lie outside the argument principle

Statement refuted

Refuted claim: the argument principle still applies unchanged when the enclosed singularity is essential.

Facts & Assumptions

Given: The punctured unit disc and the function f(z)=e1/z1.

[L1]

The argument principle requires a finite zero-minus-pole count for a meromorphic function (The argument principle for an admissible null-homologous cycle).

Counterexample

technique · direct
1.1

The equation e1/z1=0 is equivalent to 1/z=2πik for some nonzero integer k, so the zeros are zk=12πik(kZ{0}). These are infinitely many distinct points, and they accumulate at 0.

givenalgebra
2.1

Thus every small circle around 0 encloses infinitely many zeros of e1/z1, while 0 is an essential singularity rather than a pole. The finite meromorphic count required by [L1] is unavailable, so the naive extension of the argument principle to essential singularities is false.

step 1.1L1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources