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CounterexampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-21
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Two four-point probability measures agree on a generating family that is not a pi-system

Statement refuted

Agreement on a family that merely generates the sigma-algebra does not determine a measure. Intersection closure in the pi-system uniqueness theorem is essential.

Facts & Assumptions

Given: The four-point set X={NW,NE,SW,SE} and the family G consisting of X, the north and south rows, and the west and east columns.

[L1]

A probability measure is a measure with total mass 1 (Probability measures and probability spaces).

[L2]

The generated sigma-algebra is the smallest sigma-algebra containing the generating family (The sigma-algebra generated by a family of sets).

[L3]

A pi-system is closed under intersections (Pi-systems), and the uniqueness theorem requires agreement on a generating pi-system with a finite-measure exhaustion (Measures agreeing on a generating pi-system are equal under an increasing finite-measure exhaustion from that pi-system).

Counterexample

technique · direct
1.1

Give μ masses (1/2,0,0,1/2) at (NW,NE,SW,SE) and give ν masses (0,1/2,1/2,0). Finite summation over subsets defines probability measures on P(X).

givenL1
1.2

Intersecting rows with columns produces every singleton, so σX(G)=P(X); a singleton intersection is absent from G, so G is not a pi-system. The constant sequence X,X, is an increasing finite-measure exhaustion lying in G.

givenL1L2L3
2.1

Every row and column contains exactly one μ-atom and one ν-atom of mass 1/2, and both measures give X mass 1, so the measures agree on G.

givenstep 1.1algebra
3.1

The measures are unequal because μ({NW})=1/2 and ν({NW})=0, despite steps 2.1 and 1.2. The family satisfies the generating and finite-measure exhaustion hypotheses and violates the pi-system hypothesis of [L3].

step 1.1step 2.1step 1.2L3

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