Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-13
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Markov's conclusion can fail without nonnegativity

Statement refuted

The conclusion of Markov's inequality remains valid when the hypothesis X0 is removed.

Facts & Assumptions

Given: The uniform two-point probability space and a random variable X taking values 1 and 3.

[L1]

Each point in a uniform two-point space has probability 1/2 (The uniform probability space on a nonempty finite set).

[L3]

Markov's theorem assumes that X is nonnegative (Markov's inequality on a finite probability space).

Counterexample

technique · constructive
1.1

For the constructed two-valued variable, direct calculation gives E[X]=(13)/2=1.

givenL1L2algebraconstruct
2.1

At threshold a=1, P(X1)=1/2, while E[X]/a=1.

step 1.1L1algebra
3.1

The purported conclusion would be 1/21, which is false. This refutes removal of the nonnegativity hypothesis, not [L3].

step 2.1L3discharge-construct

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 42 results over 15 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources