Alphabeta Math
CounterexampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Over Z/4\mathbb Z/4, a nonconstant polynomial can be a unit and product degree can drop

Statement refuted

For every commutative ring RR, every unit of R[x]R[x] is constant and degrees add under multiplication of nonzero polynomials.

Facts & Assumptions

Given: The ring R=Z/4R=\mathbb Z/4 and the polynomial u=1+2xR[x]u=1+2x\in R[x].

[L1]

Over a commutative ring, product degree is at most the sum of the degrees, and the coefficient at that sum is the product of the leading coefficients (Degree inequalities for sums and products over a commutative ring).

[L2]

The ring Z/4\mathbb Z/4 is the quotient ring Z/4Z\mathbb Z/4\mathbb Z, so 4=04=0 in it (For every nNn\in\mathbb N, the congruence-class ring Z/n\mathbb Z/n is the quotient ring Z/nZ\mathbb Z/n\mathbb Z).

Counterexample

technique · direct
1.1

In R[x]R[x], u2=(1+2x)2=1+4x+4x2=1u^2=(1+2x)^2=1+4x+4x^2=1 by [L2], so the nonconstant polynomial uu is a unit and is its own inverse.

givenL2algebra
2.1

Both factors uu have degree 11, but their product has degree 00; [L1] permits this drop because the top coefficient is 22=02\cdot2=0 in RR, so both parts of the statement are refuted.

step 1.1L1L2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 37 results over 11 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources