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CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedaudited 2026-09-22
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Norm need not equal spectral radius

Statement refuted

Assume the Axiom of Choice (The Axiom of Choice). In M2(C) with the Euclidean operator norm the matrix

E12=(0100)

has operator norm E12=1 and spectral radius r(E12)=0 (Spectral radius). So the norm of an element of a unital Banach algebra need not equal its spectral radius.

Facts & Assumptions

Given: The Axiom of Choice, the algebra M2(C) with the Euclidean operator norm, and the matrix E12 acting on column vectors (x,y)C2.

[L1]

In M2(C) the spectrum of a matrix A is {λ:det(λIA)=0} and the algebra is a unital Banach algebra with the operator norm (Spectrum in a finite-dimensional matrix algebra).

[L2]

The spectral radius is r(a)=max{z:zσ(a)}, and it is defined under the Axiom of Choice (Spectral radius, Spectrum and resolvent set in a Banach algebra).

Counterexample

technique · direct
1.1

E12(x,y)=(y,0), so E12(x,y)=y(x,y) for every (x,y)C2 (operator norm on the Euclidean plane), with equality at (0,1); hence E12=1.

algebra
2.1

E122=0, and det(λIE12)=λ2, whose only zero is λ=0; by [L1] the spectrum is σ(E12)={0}.

step 1.1L1algebra
3.1

By [L2] the spectral radius is r(E12)=max{z:z{0}}=0<1=E12; hence the two quantities differ for this element.

step 1.1step 2.1L2algebra

Remarks

  • The witness is a nonzero nilpotent of minimal size. E12 is the smallest nonzero nilpotent: its square vanishes and its norm is one, so the gap between norm and spectral radius is already visible on the unit sphere of the matrix algebra.

  • The spectral radius formula records the same gap asymptotically. E12n1/n equals 1 for n=1 and 0 for n2, and its limit is 0=r(E12), in agreement with Spectral radius formula.

Depends on

Used by

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