Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-12
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The cusp parametrization t mapsto (t^2,t^3) is bijective but not an isomorphism

Statement refuted

A bijective morphism of affine varieties need not be an isomorphism.

Let C:=V(v2u3)Ak2, and define ν:Ak1C,t(t2,t3). Every point of C has the form (a2,a3) for a unique ak, so ν is bijection on points.

Its pullback on coordinate rings is k[C]=k[u,v]/(v2u3)k[t],ut2,vt3. This homomorphism is injective but not surjective, because t is not in its image. Hence Affine morphisms are contravariantly equivalent to coordinate-ring homomorphisms shows that ν is not an isomorphism.

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