Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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Forms of discriminant 24 need not be properly equivalent

Statement refuted

Two integral binary quadratic forms with the same discriminant need not be properly equivalent. The forms

f=(1,0,6)andg=(2,0,3)

both have discriminant 24, but they are not properly equivalent.

Facts & Assumptions

Given: The forms f=(1,0,6) and g=(2,0,3).

[F1]

The discriminant of (a,b,c) is b24ac (The discriminant of a binary quadratic form).

[L2]

A form represents n when it takes the value n at some integer pair (Integers represented, and primitively represented, by a binary quadratic form).

Counterexample

technique · direct
1.1

The discriminants are 02416=24 and 02423=24.

F1givenalgebra
1.2

The form f represents 1, since f(1,0)=1.

L2givenalgebra
1.3

The form g does not represent 1: if g(x,y)=1, then 2x2+3y2=1, but y0 would force the left-hand side to be at least 3, while y=0 would give 2x2=1, impossible in integers.

L2givenalgebra
2.1

Since f and g do not represent the same integers, [L1] shows that they are not properly equivalent.

L1step 1.2step 1.3

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources