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Symmetrization does not preserve products in sl2

Statement refuted

PBW symmetrization preserves products in sl2.

Facts & Assumptions

Given: sl2 over a characteristic-zero field, with [h,e]=2e.

[L1]

Symmetrization satisfies sym⁡(eh)=12(eh+he) and is a vector-space isomorphism (PBW symmetrization in characteristic zero).

Counterexample

technique · direct computation
1.1givenL1algebra

In U(sl2), he−eh=2e, so sym⁡(eh)=12(eh+he)=eh+e.

2.1step 1.1L1algebra

On degree-one factors, sym⁡(e)sym⁡(h)=eh. PBW injectivity from [L1] gives e≠0 in the enveloping algebra, so eh+e≠eh.

3.1step 2.1∎

Therefore symmetrization does not preserve this product and is not an algebra homomorphism.

Depends on

Used by

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Dependency tree · two levels

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Sources