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CounterexampleConstruction: AI-adaptedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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The square-affine group of F_7 is 2-homogeneous but not 2-transitive

Statement refuted

Every 2-homogeneous action is 2-transitive.

Facts & Assumptions

Given: The subgroup G:={ x↦ax+b:a∈{1,2,4}, b∈F7 } of the affine group of F7.

[L1]

A 2-homogeneous action sends any 2-element subset to any other, while a 2-transitive action sends any ordered pair of distinct points to any other ordered such pair (k-transitive and k-homogeneous actions).

Counterexample

technique · direct
1.1L1algebra

The nonzero squares in F7 are {1,2,4}, and every nonzero element is either a square or the negative of a square. So for any distinct x,y,u,v∈F7, after possibly swapping u and v there is a∈{1,2,4} with a(y−x)=v−u. Then the affine map z↦a(z−x)+u lies in G and sends {x,y} to {u,v}. Thus the action is 2-homogeneous.

1.2L1algebra

Every element of G multiplies differences by a square: if g(z)=az+b, then g(y)−g(x)=a(y−x) with a∈{1,2,4}. Since 1 is a square and 3 is not, no element of G sends the ordered pair (0,1) to (0,3). So the action is not 2-transitive.

2.1step 1.1step 1.2∎

Step 1.1 gives 2-homogeneity while step 1.2 denies 2-transitivity, refuting the statement.

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources