Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Weak star and weak topologies on a dual can differ

Statement refuted

The weak and weak-star topologies on a normed dual always coincide. They differ on 1=c0 over either the real or complex scalars.

Facts & Assumptions

[F1]

The dual of c0 is isometrically 1 under the bilinear pairing a(x)=kakxk (The continuous dual of c0 is ell-one).

[F2]

Weak-star convergence tests vectors of the specified predual (Weak star convergence), whereas weak convergence tests all bounded functionals on the space in question (Weak convergence of nets and sequences).

Counterexample

Given: en1=c0, the coordinate unit sequences.

1.1

For every xc0, en(x)=xn0 by the definition of c0. Hence en converges to zero for σ(1,c0).

givenF1F2
2.1

The scalar-linear map H(a)=kak on 1 is well-defined by absolute convergence and satisfies H(a)a1. Thus it is a weakly continuous functional on 1, but H(en)=1 for all n. The sequence is not weakly null. Equal topologies would have the same convergent sequences and limits, so the weak and the specified weak-star topologies differ.

step 1.1F2algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources