Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The zero-measure Lp boundary

Statement refuted

For every finite compactly supported measure μ and every 1<p<∞, a single-hidden-layer network family is dense in Lp(μ) only if its activation is not polynomial almost everywhere.

Facts & Assumptions

Given: The zero measure μ=0, an exponent 1<p<∞, and the constant activation σ(t)=1.

[F1]

Lp(μ) is the space of finite-p-integral functions modulo equality almost everywhere (The function space Lp(μ) for 0<p<∞, The space Lp(μ) as the quotient by null functions).

[F2]

The single-hidden-layer family includes the zero function by taking width zero and output bias zero (Single-hidden-layer network realization).

[F3]

A measure is a nonnegative countably additive set function on its sigma-algebra; the zero measure assigns zero to every measurable set (Measures on sigma-algebras).

Counterexample

1.1givenF3algebra

The constant activation σ(t)=1 is a polynomial, and the zero measure is finite, compactly supported, and absolutely continuous with respect to Lebesgue measure by [F3].

1.2givenF1

Since every measurable function has Lp(0) seminorm zero, the quotient space Lp(0) contains only its zero class by [F1].

2.1step 1.1step 1.2F2∎

The network family contains the zero function by [F2], whose class is the only element of Lp(0). Thus it is dense despite the polynomial activation, refuting the unrestricted “only if” claim.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources