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A split short exact sequence admits the direct-sum resolution
Statement
Assume the Axiom of Dependent Choice.
Let
be a split short exact sequence, and let projective resolutions of and be given. Then the sequence admits a projective resolution of whose degree- term is the direct sum of the chosen side terms.
Facts & Assumptions
Given: A split short exact sequence and chosen projective resolutions of and .
The horseshoe lemma produces a middle projective resolution (The horseshoe lemma for projective resolutions).
A split short exact sequence identifies the middle object with the direct sum of the two ends (Split short exact sequence in an abelian category).
Proof
By [L2], identify with . Applying [L1] to the chosen projective resolutions and the chosen splitting maps gives a middle resolution whose degree- term is and whose augmentation is the direct-sum augmentation.
Under that identification, the differentials are exactly the direct-sum differentials of the two side resolutions. Hence the split short exact sequence admits the direct-sum resolution.
Depends on
Used by
Dependency tree · two levels
8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Charles A. Weibel, An Introduction to Homological Algebra (standard reference, not scraped)
- Romyar Sharifi, Homological Algebra (standard reference, not scraped)