Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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Abelian normal subgroups of faithful primitive actions are regular

Statement

Let G act faithfully and primitively on Ω, and let N⊴G be a nontrivial abelian normal subgroup. Then the action of N on Ω is regular.

Facts & Assumptions

Given: A faithful primitive action of G on Ω and a nontrivial abelian normal subgroup N⊴G.

[L1]

In a faithful primitive action, every nontrivial normal subgroup is transitive (Normal subgroups of a primitive action are transitive or lie in the kernel).

[L2]

An action is regular exactly when it is both transitive and free (Regular actions).

Proof

technique · direct
1.1L1

By [L1], the action of N on Ω is transitive.

2.1step 1.1givenchoose

Fix α∈Ω, and suppose n∈N fixes α. For any β∈Ω, step 1.1 gives m∈N with β=m⋅α. Since N is abelian, n⋅β=n⋅(m⋅α)=(nm)⋅α=(mn)⋅α=m⋅(n⋅α)=m⋅α=β.

3.1step 2.1

Step 2.1 shows that any element of N fixing one point fixes every point. Faithfulness of the ambient action therefore forces that element to be the identity. So the action of N is free.

4.1step 1.1step 3.1L2∎

Steps 1.1 and 3.1 make the action of N transitive and free, hence regular by [L2].

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources