Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-11
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Isomorphism classes of abelian groups of order p^n are counted by partitions of n

Statement

For a prime p and n>0, isomorphism classes of abelian groups of order pn are in bijection with partitions of n. For n=0, the unique group is the trivial group and corresponds separately to the empty partition.

Facts & Assumptions

Given: The objects and hypotheses in the statement.

[L1]

Every finite abelian group is isomorphic to a finite direct product of cyclic groups of prime-power order. The multiset of their orders is uniquely determined by the group, up to permutation of the factors. (Fundamental theorem of finite abelian groups: elementary-divisor form).

[L2]

For n>0, a partition of n is a finite nondecreasing list of positive integers (e1,…,er) with e1+⋯+er=n, using finite natural sums as in def-nat-finite-sum-and-product and naturals as in def-natural-numbers. Equality is equality of these lists. The nondecreasing convention removes permutations from the data. (Partitions of a positive integer).

[L3]

If G and H are finite groups, then their external direct product is finite and has order ∣G×H∣=∣G∣ ∣H∣. (For finite groups G and H, ∣G×H∣=∣G∣ ∣H∣).

Proof

technique · direct
1.1

The elementary-divisor theorem writes such a group uniquely as Cpe1×⋯×Cper with the positive exponents arranged nondecreasingly. The product-order formula gives e1+⋯+er=n.

givenL1L2L3
2.1

Thus the exponents form a partition of n, and every partition constructs a group of order pn. Uniqueness of elementary divisors makes the two constructions inverse.

step 1.1∎

Depends on

Used by

Dependency tree · two levels

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Sources